Lesson 15 of 30 · Classical Mechanics

Kinematics in One and Two Dimensions

Kinematics

Describing motion

Kinematics describes how things move without yet asking why — that “why” is the next lesson on forces. Motion is built from three quantities, each the calculus rate of the one before it 1. Position \(x(t)\) locates the object; velocity is its rate of change,

\[v = \frac{dx}{dt},\]

and acceleration is the rate of change of velocity, \(a = \dfrac{dv}{dt} = \dfrac{d^2x}{dt^2}\). These are the same derivatives from the math course, now attached to physical meaning: velocity is the slope of the position graph, acceleration the slope of the velocity graph.

Constant-acceleration equations

A great many problems involve (at least approximately) constant acceleration — most famously free fall near Earth’s surface, where \(a = -g\) with \(g \approx 9.8\ \text{m/s}^2\). Integrating \(a = \text{const}\) twice gives the three kinematic equations that solve nearly every introductory motion problem 1:

\[v = v_0 + a t,$$ $$x = x_0 + v_0 t + \tfrac{1}{2} a t^2,$$ $$v^2 = v_0^2 + 2a\,(x - x_0).\]

The third is the time-free combination — useful when you know distances and speeds but not the elapsed time. Choosing which equation to use is mostly a matter of identifying which quantity is missing.

Two dimensions: independent components

Motion in a plane is not a new theory — it is two one-dimensional problems running at once. The key insight is that the horizontal and vertical components are independent: gravity affects the vertical motion and leaves the horizontal motion untouched 1. A velocity at angle \(\theta\) splits into \(v_x = v\cos\theta\) and \(v_y = v\sin\theta\), and each component obeys the one-dimensional equations above on its own.

Projectile motion

The classic application is the projectile: launched at speed \(v_0\) and angle \(\theta\), with gravity the only force. Horizontally the motion is uniform (\(a_x = 0\), so \(x = v_0\cos\theta\, t\)); vertically it is uniformly accelerated (\(a_y = -g\)). Eliminating time gives the parabolic path shown below.

Projectile trajectories for a fixed launch speed at three angles. Horizontal motion is uniform; vertical motion is uniformly accelerated by gravity.
Projectile trajectories for a fixed launch speed at three angles. Horizontal motion is uniform; vertical motion is uniformly accelerated by gravity. source

From the components you can derive the familiar results — the time of flight, the peak height, and the range on level ground,

\[R = \frac{v_0^2 \sin(2\theta)}{g},\]

which is maximized at \(\theta = 45^\circ\), as the equal-range pairing of the \(30^\circ\) and \(60^\circ\) curves in the figure hints 1. With motion described, the next lesson introduces the forces that cause acceleration.

References

  1. University Physics, Volumes 1–3. OpenStax (Rice University). verified Cited at: Vol 1, Ch. 3; Vol 1, Ch. 4.