Lesson 15 of 30 · Classical Mechanics
Kinematics in One and Two Dimensions
Describing motion
Kinematics describes how things move without yet asking why — that “why” is the next lesson on forces. Motion is built from three quantities, each the calculus rate of the one before it 1. Position \(x(t)\) locates the object; velocity is its rate of change,
and acceleration is the rate of change of velocity, \(a = \dfrac{dv}{dt} = \dfrac{d^2x}{dt^2}\). These are the same derivatives from the math course, now attached to physical meaning: velocity is the slope of the position graph, acceleration the slope of the velocity graph.
Constant-acceleration equations
A great many problems involve (at least approximately) constant acceleration — most famously free fall near Earth’s surface, where \(a = -g\) with \(g \approx 9.8\ \text{m/s}^2\). Integrating \(a = \text{const}\) twice gives the three kinematic equations that solve nearly every introductory motion problem 1:
The third is the time-free combination — useful when you know distances and speeds but not the elapsed time. Choosing which equation to use is mostly a matter of identifying which quantity is missing.
Two dimensions: independent components
Motion in a plane is not a new theory — it is two one-dimensional problems running at once. The key insight is that the horizontal and vertical components are independent: gravity affects the vertical motion and leaves the horizontal motion untouched 1. A velocity at angle \(\theta\) splits into \(v_x = v\cos\theta\) and \(v_y = v\sin\theta\), and each component obeys the one-dimensional equations above on its own.
Projectile motion
The classic application is the projectile: launched at speed \(v_0\) and angle \(\theta\), with gravity the only force. Horizontally the motion is uniform (\(a_x = 0\), so \(x = v_0\cos\theta\, t\)); vertically it is uniformly accelerated (\(a_y = -g\)). Eliminating time gives the parabolic path shown below.

From the components you can derive the familiar results — the time of flight, the peak height, and the range on level ground,
which is maximized at \(\theta = 45^\circ\), as the equal-range pairing of the \(30^\circ\) and \(60^\circ\) curves in the figure hints 1. With motion described, the next lesson introduces the forces that cause acceleration.
References
- University Physics, Volumes 1–3. OpenStax (Rice University). verified Cited at: Vol 1, Ch. 3; Vol 1, Ch. 4.